Tictactoe 游戏 没有运算符"=="与这些操作数匹配
tictactoe game No operator "==" matches these operands
它可能效率很低,也很混乱,但这是我的问题-它上面写着"zz==defo&&zo==defo"之类的东西。等号用红色下划线表示错误:没有运算符"=="匹配这些操作数,当我运行时,我得到一个太长的错误,无法在这里发布-http://pastebin.com/KTEM0MZK
我做错了什么?提前感谢
这是我的代码-
#include <iostream>
#include <cstdlib> // for rand() and srand()
#include <ctime> // for time()
using namespace std;
string random1(){
srand(((time(0) - 23) * time(0)) - (9*time(0)));
if (rand() % 2 == 0){
return "1";
} else {
return "0";
}
}
string random2(){
srand((((time(0) - 89) * time(0)) - (9*time(0)) / 3) - 99);
if (rand() % 2 == 0){
return "1";
} else {
return "0";
}
}
int main(){
string zz = "-";
string zo = "-";
string zt = "-";
string oz = "-";
string oo = "-";
string ot = "-";
string tz = "-";
string to = "-";
string tt = "-";
for(int a = 1;a<=9;a++){
srand ( time(NULL) - 8 );
int ran1 = rand() % 3;
srand ( time(NULL) * 2);
int ran2 = rand() % 3;
int tote = (ran1 * 10) + ran2;
cout << endl << "format- 0 = zero, 1 = one, 2 = two" << endl;
int input;
cin >> input;
if(input == 00){
zz = "X";
} else if(input == 01){
zo = "X";
} else if(input == 02){
zt = "X";
} else if(input == 10){
oz = "X";
} else if(input == 11){
oo = "X";
} else if(input == 12){
ot = "X";
} else if(input == 20){
tz = "X";
} else if(input == 21){
to = "X";
} else if(input == 22){
tt = "X";
}
// now for the computers part
if(tote == 00){
zz = "O";
} else if(tote == 01){
zo = "O";
} else if(tote == 02){
zt = "O";
} else if(tote == 10){
oz = "O";
} else if(tote == 11){
oo = "O";
} else if(tote == 12){
ot = "O";
} else if(tote == 20){
tz = "O";
} else if(tote == 21){
to = "O";
} else if(tote == 22){
tt = "O";
}
printf ("|%d|%d|%d", zz, zo, zt);
cout << endl;
printf ("|%d|%d|%d", oz, oo, ot);
cout << endl;
printf ("|%d|%d|%d", tz, to, tt);
if(zz == "X" && zo == "X" && zt == "X" || oz == "X" && oo == "X" && ot == "X" || tz == "X" && to == "X" && tt == "X" || zz == "X" && oz == "X" && tz == "X" || zo == "X" && oo == "X" && to == "X" || zt == "X" && ot == "X" && tt == "X" || zz == "X" && oo == "X" && tt == "X"){
cout << endl << "X WINNER";
break;
}
if(zz == "O" && zo == "O" && zt == "O" || oz == "O" && oo == "O" && ot == "O" || tz == "O" && to == "O" && tt == "O" || zz == "O" && oz == "O" && tz == "O" || zo == "O" && oo == "O" && to == "O" || zt == "O" && ot == "O" && tt == "O" || zz == "O" && oo == "O" && tt == "O"){
cout << endl << "O WINNER";
break;
}
}
system("pause");
return 0;
}
您需要#include <string>
,其中定义了operator==
。
而且,正如jrok已经指出的,您正在将std::string
传递给printf()
:使用cout
(正如您已经使用的那样)。
您正试图将std::string
s传递给printf
,这是一个C库函数。此外,格式字符串表示您将传递整数("|%d|%d|%d"
)。
printf
只接受c风格的字符串,所以如果这是你想要的,你可以说:
printf("|%s|%s|%s", ot.c_str(), zz.c_str(), ...);
也与您的代码有关
if(zz == "X" && zo == "X" && zt == "X" || oz == "X" && oo == "X" && ot == "X" || tz == "X" && to == "X" && tt == "X" || zz == "X" && oz == "X" && tz == "X" || zo == "X" && oo == "X" && to == "X" || zt == "X" && ot == "X" && tt == "X" || zz == "X" && oo == "X" && tt == "X"){
cout << endl << "X WINNER";
应该是
if((zz == "X" && zo == "X" && zt == "X") || (oz == "X" && oo == "X" && ot == "X") || (tz == "X" && to == "X" && tt == "X") || (zz == "X" && oz == "X" && tz == "X") || (zo == "X" && oo == "X" && to == "X") || (zt == "X" && ot == "X" && tt == "X") || (zz == "X" && oo == "X" && tt == "X")){
cout << endl << "X WINNER";
你的比较是看每个单独的分数,而不是看分数的组合。每组3个左右的()将给出您想要的结果。
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