编译错误:链接器命令失败，退出代码为 1

Compile Error: linker command failed with exit code 1

本文关键字：退出 代码 失败 命令 错误 链接 编译      更新时间：2023-10-16

我是C++新手，并试图制作一个简单的程序。

但是我收到此错误：

    Undefined symbols for architecture x86_64:
  "_main", referenced from:
     implicit entry/start for main executable
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
[Finished in 0.4s with exit code 1]

从此代码：

#include <iostream>
using namespace std;
// Lets add some global variables
int FirstNumber = 0;
int SecondNumber = 0;
int MultiNum = 0;
void MultiNumbers ()
{
    cout << "Enter the first number: ";
    cin >> FirstNumber;
    cout << "Enter the second number: ";
    cin >> SecondNumber;
    // Multiply two numbers...
    MultiNum = FirstNumber * SecondNumber;
    // Display result
    cout << "Displaying result from MultiNumbers(): ";
    cout << FirstNumber << " x " << SecondNumber;
    cout << " = " << MultiNum << endl;
}
int Main ()
{
    cout << "This program will help you to multiply two numbers" << endl;
    // Now call the function that does all the work
    MultiNumbers();
    cout << "Displaying from main(): ";
    // This line will not compile and work because of the global variables
    cout << FirstNumber << " x " << SecondNumber;
    cout << " = " << MultiNum << endl;
    return 0;
}

我尝试在崇高上检查我的编译器，使用 g++ -o 测试测试在终端中编译.cpp

但似乎没有任何帮助。

我的理解是，我已经在上面定义了MultiNumbers（），然后我在Main（）中调用它...但我似乎错过了一些东西...

建议？

C++区分

大小写。这：

int Main ()

应该是

int main ()
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