案例语句不执行

Case Statement does not execute

本文关键字:执行 语句 案例      更新时间:2023-10-16
目前,

这对我来说是一个越来越大的烦恼来源,当我按下相应的案例按钮(它们在上面初始化)时,它们实际上并没有执行,我被困在菜单中。

敢肯定这非常简单,我只是没有看到它。

编辑:根据要求添加更多

const int POKER = 1;
const int EVAL = 2;
const int EXIT = 3;
const char FIVE_CARD = 'a';
const char TEXAS = 'b';
const char OMAHA = 'c';
const char SEVEN_CARD = 'd';
const char GO_BACK = 'e';
const char MENU[] = "nPlease choose an option from the following:n"
                    "1) Play Pokern2) Set Evaluation Methodn3) Quitn: ";
const char POKER_MENU[] = "nPlease choose your game:n"
                          "a) 5 Card Drawnb) Texas Hold 'Emnc) Omaha Highn"
                          "d) 7 Card Studne) Go backn: ";
int main()
{
int choice = 0;
char poker_choice;
do
{
    choice = askForInt(MENU, EXIT, POKER);
    switch(choice)
    {
        case POKER :
            do
            {
                choice = askForChar(POKER_MENU, GO_BACK, FIVE_CARD);
                switch(poker_choice)
                {
                    case FIVE_CARD :
                        std::cout << "Not implemented yet" << std::endl;
                        break;
                    case TEXAS :
                        std::cout << "Not implemented yet" << std::endl;
                        break;
                    case OMAHA :
                        std::cout << "Not implemented yet" << std::endl;
                        break;
                    case SEVEN_CARD :
                        std::cout << "Not implemented yet" << std::endl;
                        break;
                    case GO_BACK :
                        break;
                }
            }while(poker_choice != GO_BACK);
        case EVAL :
            std::cout << "Not implemented yet" << std::endl;
            break;
        case EXIT :
            break;
    }
}while(choice != EXIT);

choice = askForChar(POKER_MENU, GO_BACK, FIVE_CARD);

应该是 poker_choice = askForChar(POKER_MENU, GO_BACK, FIVE_CARD);

既然你提到这是在一个方法里面,

这里要检查的事情很少;

  • 进入方法后,只需打印poker_choice,看看您的值是否正确传递。
  • 检查是否所有情况都FIVE_CARD,TEXAS 都声明为相同数据类型的常量。

您的错误似乎在这一行:

choice = askForChar(POKER_MENU, GO_BACK, FIVE_CARD);

switch中测试poker_choice,但将值分配给choice

它应该是:

   poker_choice = askForChar(POKER_MENU, GO_BACK, FIVE_CARD);
// ^^^^^^
   switch(poker_choice)
   // ...