使用C++当我同时具有整数和字符数组时，如何将.txt文件中的数据作为链表的一部分访问

我的问题是我在.txt文件中有许多文件类型int以及长度为50的char数组。我有一个链表（队列结构）程序，它本质上是一个事件日历，具有用于搜索特定条目、星期几、日期和消息（有关事件的信息）的索引。无需从文件中读取，我可以创建事件、删除事件、修改事件、显示所有事件或显示单个事件。我需要补充的是：1.程序终止时保存所有事件的能力。2.然后下次打开它时，我需要能够从.txt文件中读取您的信息，并为.txt文件中的每个事件创建一个新事件。我的文本文件条目.txt显示在代码的正上方。每行如下：1.索引，2.星期几（星期日=1），3。日， 4.月， 5.年， 6.消息。在下面，它在一行上显示每个事件，但在我的.txt文件中，每个数字/字符都是一个新行。

142242015
Baseball_game_at_7231332015
This_event_is_for_nothing351762015生日

#include <iostream>
#include <fstream>
#include <string>
#include <ctime>
#include <cmath>
using namespace std;
class Event{
protected:
    int index;
    enum DAY{Sunday=1, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday};
    int date[3];
    char msg[50];
public:
    Event *next;
    Event *prev;
    Event(){
        next=NULL;
        prev=NULL;
    }
    int a;
    int day, day1;
    virtual void getindex(int b){   
        index=b;
    }
    virtual int getindex2(){
        a=index;
        return a;
    }
    virtual void getindex3(int c){
        index=c;
    }
    virtual void getday2(int d){
        day=d;
    }
    virtual void getdate2(int e, int f, int g){
        date[0]=e;
        date[1]=f;
        date[2]=g;
    }
    virtual void getmessage2(char h[50]){
        msg=h;
    }
        virtual void getdate(){
        cout<<"nOptions:n1. Sundayn2. Mondayn3. Tuesdayn4. Wednesdayn5. Thursdayn6. Fridayn7. SaturdaynWhich day would you like to select (enter the day): ";
        cin>>day;   
        cout<<"Please enter the date you would like to use (In the form of dd mm yyyy): ";
        cin>>date[0];
        cin>>date[1];
        cin>>date[2];
    }
    virtual void getcurrentdate(){
        time_t now=time(0);
        tm *local=localtime(&now);
        time_t y=1900+local->tm_year;
        time_t m=1+local->tm_mon;
        time_t d=local->tm_mday;
        time_t day1=local->tm_wday;
        day=day1+1;
        date[0]=d;
        date[1]=m;
        date[2]=y;
        }
    virtual void getmessage(){
        cout<<"Please enter your message (Use _ for any spaces): ";
        cin>>msg;
    }
    virtual void display(){
        cout<<"nThe index is: "<<index<<endl;
        switch(day){
        case Sunday:
            cout<<"The day of the week is: Sunday"<<endl;
            break;
        case Monday:
            cout<<"The day of the week is: Monday"<<endl;
            break;
        case Tuesday:
            cout<<"The day of the week is: Tuesday"<<endl;
            break;
        case Wednesday:
            cout<<"The day of the week is: Wednesday"<<endl;
            break;
        case Thursday:
            cout<<"The day of the week is: Thursday"<<endl;
            break;
        case Friday:
            cout<<"The day of the week is: Friday"<<endl;
            break;
        case Saturday:
            cout<<"The day of the week is: Saturday"<<endl;
            break;
        }
        cout<<"The date is: "<<date[0]<<"/"<<date[1]<<"/"<<date[2]<<endl;
        cout<<"The message is: "<<msg<<endl;
    }
};
 class Queue{
Event *Front, *Rear;
public:
Queue(){
        Front=NULL;
        Rear=NULL;
    }
int index;
int input4;
void newevent(int x){
        Event *temp;
        temp=new Event;
        if(Front==NULL){
                Front=temp;
                Rear=Front;
        temp->prev=NULL;
        }else{
                Rear->next=temp;
                temp->next=NULL;
        temp->prev=Rear;
        Rear=temp;
        }
    index=x;
    temp->getindex(index);
    cout<<"nOptions:n1. Enter a date manuallyn2. Use the current system date and timenWhat would you like to do: ";
    cin>>input4;
    switch(input4){
    case 1: // Get date manually
        temp->getdate();
        break;
    case 2: // Get current date
        temp->getcurrentdate();
        break;
    }
    temp->getmessage();
    temp->display();
    temp=NULL;
    }
int p;
Event *temp2;
void deleteevent(){
    Event *temp=Front;
    Front=temp->next;
    delete temp;
}
int c,d, input1, input3;
void modifyevent(int z){
    d=z;
    Event *temp=Front;
    while(temp!=NULL){
        for(c=1;c<d;c++){
            temp=temp->next;
        }
        input1=0;
        while(input1!=3){
            cout<<"nOptions:n1. Change the daten2. Change the messagen3. exitnWhat would you like to update: ";
            cin>>input1;
            switch(input1){
            case 1: // Change date
                cout<<"Options:n1. Enter a date manuallyn2. Use the current system date and timenWhat would you like to do: ";
                cin>>input3;
                switch(input3){
                case 1: // Get date manually
                    temp->getdate();
                    break;
                case 2: // Get current date
                    temp->getcurrentdate();
                    break;
                }
                break;
            case 2: // Change message
                temp->getmessage();
                break;
            case 3: // Exit
                break;
            default:
                cout<<"You entered an invalid number!";
            }
        }
        temp=NULL;
    }
}
int e,f;
void display(int z){
    f=z;
    Event *temp=Front;
    while(temp!=NULL){
        for(e=1;e<f;e++){
            temp=temp->next;
        }
        temp->display();
        temp->next;
        temp=NULL;
    }
}

void displayall(){
        Event *temp=Front;
        while(temp!=NULL){
                temp->display();
                cout<<"n";
                temp=temp->next;
        }
    }
int end;
int x;
int y;
int a;
int b;
int g[3];
char h[50];
void readfromfile(){ // This was my attempt at the problem
    ifstream fin;
    fin.open("entries.txt");
    Event *temp;
    x=1;
    y=1;
    end=1;
    while(fin>>y){
        end++;          
    }
    for(x;x<end;x++) {  // till end-of-file
        a=fin>>x;
        x++;
        b=fin>>x;
        x++;
        g[0]=fin>>x;
        x++;
        g[1]=fin>>x;
        x++;
        g[2]=fin>>x;
        x++;
        h=fin.getline(x);
        temp=new Event;
            if(Front==NULL){
                    Front=temp;
                    Rear=Front;
            temp->prev=NULL;
            }else{
                    Rear->next=temp;
                    temp->next=NULL;
            temp->prev=Rear;
            Rear=temp;
            }
        temp->getindex3(a);
        temp->getday2(b);
        temp->getdate2(g[0],g[1],g[2]);
        temp->getmessage2(h);
        temp=NULL;
    }
    fin.close();
}
void writetofile(){ //I understand this is blank, I havn't made it this far
}
};

int main(){
ofstream myfile;
myfile.open("entries.txt", ios::app);

cout<<"nWELCOME TO YOUR EVENT PLANNERn";
Queue a;
a.readfromfile();
int inp=0;
    int i=0;
int num=4;
    int type;
int counter=0;
int displayevent, modifyevent;
while(inp!=6){
        cout<<"nOptions:n1. Create new eventn2. Delete the oldest eventn3. Modify an eventn4. Display all eventsn5. Display a specific eventn6. Exit event plannernWhat do you want to do: ";
        cin>>inp;
        switch(inp){
        case 1: // New event
        a.newevent(num);
        num++;
        counter++;
            break;
        case 2: // Delete event
        a.deleteevent();
        counter--;
            break;
    case 3: // Modify event
        cout<<"nEnter the index of the event you would like to modify: ";
        cin>>modifyevent;
        a.modifyevent(modifyevent);
        break;
    case 4: // Display all events
        a.displayall();
            break;
        case 5: //Display single event
        cout<<"nEnter the index of the event you would like to display: ";
        cin>>displayevent;
        a.display(displayevent);
        break;
    case 6: // Exit event planner
        break;
    default:
        cout<<"You entered an invalid number"; 
        break;
        }
    }   
cout<<"The current number of events is "<<counter<<endl;
myfile.close();

return 0;
}

Queue.readfromfile（） 是我读取文件并将文件中的每个事件作为新事件输入的尝试。我需要知道如何将文本文件的每一行保存为不同的内容，以便将其发送到上面类中的函数。Queue.writetofile（） 被故意留空，因为我甚至还没有做到那么远。我应该能够很容易弄清楚。我想先读完文件。