运算符重载错误

Operator overloading error

本文关键字：错误 重载 运算符      更新时间：2023-10-16

我这里有代码，我试图理解运算符重载，我遇到了一个障碍，错误我不完全理解。该错误上有 3 个LNK2019错误，读取未解析的外部符号。我想知道错误是什么以及如何修复它。提前感谢您的帮助。

这是我的实现代码。

ComplexNumber::ComplexNumber()
{
double complexNumberValue = 0.00;
double realNumberValue = 0.00;
}
ComplexNumber::ComplexNumber(double real, double imaginary)
{
realNumberValue = real;
complexNumberValue = imaginary;
}
ComplexNumber ComplexNumber::operator*(const ComplexNumber& rho) const
{
double newValue = realNumberValue * rho.getValue();
ComplexNumber newNumber(newValue, complexNumberValue);
return newNumber;
}
ComplexNumber ComplexNumber::operator+(const ComplexNumber& rho) const
{
double newValue = realNumberValue + rho.getValue();
ComplexNumber newNumber(newValue, complexNumberValue);
return newNumber;
}
ComplexNumber ComplexNumber::operator-(const ComplexNumber& rho) const
{
double newValue = realNumberValue - rho.getValue();
ComplexNumber newNumber(newValue, complexNumberValue);
return newNumber;
}
ComplexNumber ComplexNumber::operator/(const ComplexNumber& rho) const
{
double newValue = realNumberValue / rho.getValue();
ComplexNumber newNumber(newValue, complexNumberValue);
return newNumber;
}
ComplexNumber ComplexNumber::operator=(const ComplexNumber& rho)
{
realNumberValue = rho.realNumberValue;
return *this;
}
bool operator==(const ComplexNumber& leftOp, const ComplexNumber& rightOp)
{
    if (leftOp.getValue() == rightOp.getValue())
    {
    return true;
    }
    else
    {
    return false;
    }
}
ostream& operator<<(ostream& out, const ComplexNumber& rho)
{
out << rho.getValue();
return out;
}

这是我的驱动程序代码。

#include "ComplexNumbers.h"
int main()
{
// Create complex numbers to do arithmentic with
ComplexNumber cm1(1, 2);
ComplexNumber cm2(1, -2);
// test addition operator
ComplexNumber cm3 = cm1 + cm2;
cout << cm3 << endl;
// test subtraction operator
ComplexNumber cm4 = cm1 - cm2;
cout << cm4 << endl;
// test multiplication operator
ComplexNumber cm5 = cm1 * cm2;
cout << cm5 << endl;
// test division operator
ComplexNumber cm6 = cm1 / cm2;
cout << cm6 << endl;
// test assignment operator
cm6 = cm5;
cout << cm6 << endl;
// test comparison operator
if (cm1 == cm2)
    cout << "nThey are equal.n";
else
    cout << "nThey are not equal.";
ComplexNumber cm8(1, 2);
if (cm1 == cm8)
    cout << "nThey are equal.n";
else
    cout << "nThey are not equal.";
system("PAUSE");
return 0;
}

这是请求的头文件

#include <string>
#include <iomanip>
#include <iostream>
#include <fstream>
#include <stdexcept>
using namespace std;
class ComplexNumber
{
public:
//Constructor
//Purpose: Set the value of ComplexNumber to 0
//Parameters: None
//Returns: None
ComplexNumber();
//Parameterized Constructor
//Purpose: Set the value of ComplexNumber to the parameter
//Parameters: A double, and a double
//Returns: None
ComplexNumber(double, double);
//getValue
//Purpose:Getter for complexNumberValue
//Parameters: None
//Returns: the double value of object
double getValue() const;
//plusOverload
//Purpose: Overload the + operator 
//Parameters: The ComplexNumber on the right side of the operator
//Returns: A new ComplexNumber object containing the sum
ComplexNumber operator+(const ComplexNumber&) const;
//minusOverload
//Purpose: Overload the - operator 
//Parameters: The ComplexNumber on the right side of the operator
//Returns: A new ComplexNumber object containing the difference
ComplexNumber operator-(const ComplexNumber&) const;
//multiplicationOverload
//Purpose: Overload the * operator 
//Parameters: The ComplexNumber on the right side of the operator
//Returns: A new ComplexNumber object containing the product
ComplexNumber operator*(const ComplexNumber&) const;
//divisionOverload
//Purpose: Overload the / operator 
//Parameters: The ComplexNumber on the right side of the operator
//Returns: A new ComplexNumber object containing the quotient
ComplexNumber operator/(const ComplexNumber&) const;
//assignment
//Purpose: Overload the = operator
//Parameters: The two ComplexNumbers we want to assign
//Returns: 
ComplexNumber operator=(const ComplexNumber&);
//comparison
//Purpose: Overload the == operator 
//Parameters: The two ComplexNumbers we want to compare
//Returns: 
bool operator==(const ComplexNumber&) const;
private:
double complexNumberValue;
double realNumberValue;
};
//Independant Functions
//streamInsertionOverload
//Purpose: Overload the stream insertion operator
//Parameters: The stream object to read from, and object to read to
//Returns:The stream
ostream& operator<<(const ostream&, const ComplexNumber&);

这是我的错误

错误

1 错误 LNK2019：未解析的外部符号"public： bool __thiscall ComplexNumber：：operator==（class ComplexNumber const &）const " （？？8ComplexNumber@@QBE_NABV0@@Z） 在函数 _main 中引用

错误

2 错误 LNK2019：未解析的外部符号"class std：：basic_ostream> & __cdecl 运算符<<（class std：：basic_ostream> const &，class ComplexNumber const &）" （？？6@YAAAV？$basic_ostream@DU？$char_traits@D@std@std@@ABV01@ABVComplexNumber@@@Z） 在函数_main中引用

错误

3 错误 LNK2019：未解析的外部符号"public： double __thiscall ComplexNumber：：getValue（void）const " （？getValue@ComplexNumber@@QBENXZ） 在函数"class std：：basic_ostream> & __cdecl 运算符<<（class std：：basic_ostream> &，class ComplexNumber const &）"（？？6@YAAAV？$basic_ostream@DU？$char_traits@D@std@@@std@@AAV01@ABVComplexNumber@@@Z）

错误

4 错误 LNK1120：3 个未解析的外部

我已经意识到在我的头文件中，我有定义和声明的冲突。 通过删除头文件中的 const，我能够让程序进行编译。 我还需要实现 getValue（） 函数。

相关文章：