C++出现未知错误,错误:令牌之前的预期主表达式';'

Unknown error on C++, error: expected primary expression before ';' token

本文关键字:错误 表达式 未知 C++ 令牌      更新时间:2023-10-16

C++上的未知错误,错误:';"标记之前的预期主表达式。这是我用C++编写的代码:

 #include <iostream>
 #include <math.h>
 #include <stdio.h>
 #define G 6.674E-11
 using namespace std;
 int main()
 {
 //Ms = Mass of sun, Me = Mass of Earth, Fg = Gravitational force between them, As =                                   Acceleration of Sun, Ae = Acceleration of Earth, Ve_x
 // = initial velocity of Earth in x direction, Ve_y = initial velocity of Earth in y          direction, Vs_x = initial velocity of the Sun in x direction
 // Vs_y = initial velocity of sun in y direction, t = time, F = Gravitational force   `    between the two bodies.
    float Ms, Me, Fg, As, Ae, Ve_x, Ve_y, Vs_x, Vs_y, pos_E, pos_S, r_x, r_y, r, t;
    float S_dist;
    float E_dist;
    float F;
    float Ve[2];
    float Vs[2];
    float pe[2];
    float ps[2];

  FILE *fileptr;
    cout <<"Enter mass of the Sun in kgn";
    cin >> Ms;
    cout <<"Enter mass of the earth in kgn";
    cin >> Me;
    cout <<"Enter intial velocity of the sun in x direction in m/sn";
    cin >> Vs[0];
    cout <<"Enter intial velocity of the sun in y direction in m/sn";
    cin >> Vs[1];
    cout <<"Enter intial velocity of the earth in x direction in m/sn";
    cin >> Ve[0];
    cout <<"Enter intial velocity of the earth in y direction in m/sn";
    cin >> Ve[1];
    cout <<"Enter intial position of the sun in x componentn";
    cin >> ps[0];
    cout <<"Enter intial position of the sun in y directionn";
    cin >> ps[1];
    cout <<"Enter intial position of the earth in x directionn";
    cin >> pe[0];
    cout <<"Enter intial position of the earth in y directionn";
    cin >> pe[1];

  for (t=0; t<30000; t+1)
 {
  float E_dist;
  float S_dist;
  float F;
    E_dist=sqrt( ((pe[0]-pe[0])*(pe[0]-pe[0])) + ((pe[1]-pe[1])*(pe[1]-pe[1])) );
    S_dist=sqrt( ((ps[0]-ps[0])*(ps[0]-ps[0])) + ((ps[1]-ps[1])*(ps[1]-ps[1])) );
    r_x=( (pe[0]-pe[0]) - (ps[0]-ps[0]) );
    r_y=( (pe[1]-pe[1]) - (ps[1]-ps[1]) );
    r= sqrt( (r_x)*(r_x) + (r_y)*(r_y) );
    F=(G*Me*Ms)/(r*r);
    Ae = F/Me;
    As = F/Ms;
    Ve_x = Ve[0];
    Ve_y = Ve[1];
    Vs_x = Vs[0];
    Vs_y = Vs[1];
    }
    cout<<"At time "<<t<<":n The position of the Sun is "<<S_dist<<"n The position of   the Earth is "<<E_dist
    <<"n The acceleration of the Sun is "<<As<<" n The acceleration of the Earth is "<<Ae<<" nThe velocity of the Sun in the x direction is "
    <<Vs_x<<" n The velocity of the Sun in the y direction is "<<Vs_y<<" n The velocity of the Earth in the x direction is "<<Ve_x<<
    " n The velocity of the Earth in the y direction is "<<Ve_y<<" n The gravitational force between the Sun and the Earth is "<<F<<; // ERROR OCCURRED HERE.
} 

如有任何帮助,将不胜感激,谢谢。

我认为错误是您的最后一行以这样的结尾:

<<F<<;

请注意,<<运算符仅应用于一个参数。 你的意思是写这样的东西吗?

<<F<<endl;

对于它的价值,我强烈建议将该输出行拆分为多行以清楚起见。 你现在拥有的是正确的,但它非常难以阅读。 将其重写为

cout << "At time " <<t<<":n The position of the Sun is "<<S_dist<<"n";
     << " The position of   the Earth is "<<E_dist << "n";
     << "The acceleration of the Sun is "<<As<<"n"
     << "The acceleration of the Earth is "<<Ae<<"n";
     << "The velocity of the Sun in the x direction is "<<Vs_x<<" n";
     << "The velocity of the Sun in the y direction is "<<Vs_y<<" n";
     << "The velocity of the Earth in the x direction is "<<Ve_x<< "n";
     << "The velocity of the Earth in the y direction is "<<Ve_y<<" n";
     << "The gravitational force between the Sun and the Earth is "<<F<<;

会使此错误更容易发现,因为行号信息会更有用。 另外,我建议在<<运算符之间添加空格,以使其更易于阅读。

templatetypedef 指出了编译器错误,但代码中还有另一个问题:for循环是无限的:

for (t=0; t<30000; t+1)

应该是:

for (t=0; t<30000; t++)

或者由于t是一个float,基于在浮点上使用增量(运算符++)是否不好的样式?

for (t = 0; t < 30000; t+=1.0f)

您的第一个语法错误是因为语句末尾有另一个<< cout<<F<<;将其更改为 cout<<F;,除非您有另一个 var 要打印或您想使用像 cout<<F<<endl; 这样的结束行。

你还有另一个语法错误!您的main返回 int,但您最后没有返回任何内容:

return 0;

另一个非常非常重要的问题是关于变量F

逻辑错误!!

int main()
{
....
  float S_dist; //real S_dist !!!
  float E_dist; //real E_dist !!!
  float F;      //real F !!!
  for (t=0; t<30000; t++)
  {
     float F; // just exists in for!!!
     float E_dist; //just exists in for!!!
     float E_dist; //just exists in for!!!
  ....
     F=(G*Me*Ms)/(r*r); //changing local F, which just exists in for
     E_dist=sqrt( ((pe[0]-pe[0])*(pe[0]-pe[0])) + ((pe[1]-pe[1])*(pe[1]-pe[1])) );
     S_dist=sqrt( ((ps[0]-ps[0])*(ps[0]-ps[0])) + ((ps[1]-ps[1])*(ps[1]-ps[1])) );
  }
  cout<<F<<E_dist<<S_dist; //this prints the main vars!
  return 0;
} 

请务必阅读更多有关局部变量的信息。请记住,t+1根本不会改变t!您应该在for语句的最后一部分写t++t+=1!除非你会得到一个无限循环,否则你的t根本不会增长!