分割字符串

我还没有资格评论帖子，抱歉。

我绝对推荐把这些分成不同的行。甚至取缓冲。找到部件并将其设置为适当的位置名称。这样会更容易调试，也更容易阅读。

如果一些额外的int太多，然后在调试完成后将它们合并回去。

你可以尝试的另一件事是在空格上分割缓冲行，只保留"x/y/z"，调用"被'/'分割"的函数，然后将这些存储到适当的变量中。我认为。obj文件的"f顶点/纹理/正常顶点/纹理/正常...."。

这可能对你有帮助:

它描述了如何加载和呈现一个。obj文件。

下面是如何从obj文件中读取行(包括您尝试读取的面("f"))的代码片段:

// Initialize the indexes.
    vertexIndex = 0;
    texcoordIndex = 0;
    normalIndex = 0;
    faceIndex = 0;
    // Open the file.
    fin.open(filename);
    // Check if it was successful in opening the file.
    if(fin.fail() == true)
    {
        return false;
    }
    // Read in the vertices, texture coordinates, and normals into the data structures.
    // Important: Also convert to left hand coordinate system since Maya uses right hand coordinate system.
    fin.get(input);
    while(!fin.eof())
    {
        if(input == 'v')
        {
            fin.get(input);
            // Read in the vertices.
            if(input == ' ') 
            { 
                fin >> vertices[vertexIndex].x >> vertices[vertexIndex].y >> vertices[vertexIndex].z;
                // Invert the Z vertex to change to left hand system.
                vertices[vertexIndex].z = vertices[vertexIndex].z * -1.0f;
                vertexIndex++; 
            }
            // Read in the texture uv coordinates.
            if(input == 't') 
            { 
                fin >> texcoords[texcoordIndex].x >> texcoords[texcoordIndex].y;
                // Invert the V texture coordinates to left hand system.
                texcoords[texcoordIndex].y = 1.0f - texcoords[texcoordIndex].y;
                texcoordIndex++; 
            }
            // Read in the normals.
            if(input == 'n') 
            { 
                fin >> normals[normalIndex].x >> normals[normalIndex].y >> normals[normalIndex].z;
                // Invert the Z normal to change to left hand system.
                normals[normalIndex].z = normals[normalIndex].z * -1.0f;
                normalIndex++; 
            }
        }
        // Read in the faces.
        if(input == 'f') 
        {
            fin.get(input);
            if(input == ' ')
            {
                // Read the face data in backwards to convert it to a left hand system from right hand system.
                fin >> faces[faceIndex].vIndex3 >> input2 >> faces[faceIndex].tIndex3 >> input2 >> faces[faceIndex].nIndex3
                    >> faces[faceIndex].vIndex2 >> input2 >> faces[faceIndex].tIndex2 >> input2 >> faces[faceIndex].nIndex2
                    >> faces[faceIndex].vIndex1 >> input2 >> faces[faceIndex].tIndex1 >> input2 >> faces[faceIndex].nIndex1;
                faceIndex++;
            }
        }
        // Read in the remainder of the line.
        while(input != 'n')
        {
            fin.get(input);
        }
        // Start reading the beginning of the next line.
        fin.get(input);
    }
    // Close the file.
    fin.close();

EDIT:要解决评论中的问题，这里有一个可能的解决方案:

    std::string buffer = " 1/2/3 4/5/6 7/8/9";
    string g1 = buffer.substr(1, buffer.find(' ', 1) - 1); // Pos 1 - First space
    string g2 = buffer.substr(buffer.find(' ', 1) + 1, g1.length()); // First space - Second space
    string g3 = buffer.substr(buffer.find(' ', buffer.find(' ', 1) + 1) + 1, g1.length()); // Second space - End

工作示例:http://ideone.com/07aVQO

问题是substr()的第二个参数。它应该是长度，而不是输入字符串中的位置。