C++字母 - >数字

C++ Letters -> Numbers

本文关键字:数字 gt 字母 C++      更新时间:2023-10-16

这是我第一次在Stack Overflow上发问题。我是编程新手,所以如果我说了一些奇怪或错误的话,请原谅我。在下面的文件中;它读取目录并将其保存到一个变量nAddress中。然后删除文件扩展名;将文件分成700行,每行重建扩展名;最后,文件名增加1个字母,如:testA, testB, testC, testD等。

改:电流输出:

测试是1400行,所以它输出

外种皮

必须是:

Test1

Test2

你能给我指个正确的方向吗?谢谢!
string fAddress = argv[1];
if (argc > 2)
{
    for (int i = 2; i < argc; i++)
    {
        string temp = argv[i];
        fAddress = fAddress + " " + temp;
    }
}
cout << fAddress << "n" <<endl;
// Convert to a char*
const size_t newsize = 500;
char nstring[newsize];
strcpy_s(nstring, fAddress.c_str());
strcat_s(nstring, "");

// Convert to a wchar_t*
size_t origsize = strlen(fAddress.c_str()) + 1;
size_t convertedChars = 0;
wchar_t wcstring[newsize];
mbstowcs_s(&convertedChars, wcstring, origsize, fAddress.c_str(), _TRUNCATE);
wcscat_s(wcstring, L"");

ifstream inFile;
inFile.open (wcstring);
int index = 0;
string parts[100];
string text;
for (int i = 0; i < 100; i++)
{
   parts[i] = "";
}
// get info until ; is found in each line and add it to the array of char*
while ( !inFile.eof( ) )
{
   getline(inFile, text, (char)1);
  if ( !inFile )
  {
      if (inFile.eof( ) )
         break;
      else
      {
         cout << "File error...n";
         break;
         system("PAUSE");
     }
  }
    parts[index] += text;
    index++;
}
inFile.close();
int n = fAddress.length(); // Get the total size of the file name. 
string nAddress =     "++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++";
cout<<"Removing previous file extension...n";
n = n - 4; //Remove the extension from the output file
cout<<"Removed previous file extension successfully...nn";
cout<< "Building file location and name....n";
for (int i = 0; i < n; i++)
{
   nAddress[i] = nstring[i]; //nstring hold the name
}
 cout<< "Built successfully....nn";
//Now nAddress is equal to the location and name of the file....

nAddress[n] = '0' ;//'A';
cout<<nAddress[n];
 // nAddress[n+1] = 1+48;
 //system("cls");
 cout<< "Building file extension...n"<< endl;
 for (int i = n; i < n+4; i++) // n is whatever the length of the string is. Add 4 chars onto the n.
 {
   nAddress[i+1] = nstring[i];
   fileextension = fileextension + nstring[i]; //This saves off the full file extension for later use. :)
   //cout <<nAddress;   This seems to build the extension of the file... IE .T, .TA, .TAP
  }
  cout<< "File extension built successfully...n"<< endl;
  nAddress[n+5] = '';
  //cout<< nAddress;
  string files[10];
//This is the part that searches through the file and splits it up I believe.
for (int i = 0; i < index-2; i++)
{
   files[i] = parts[0] + parts[i+1] + parts[index-1];
    //cout<< files[i]; //This line will output the entire file in the CMD window
}
//system("cls");
// The function below is where the names are dished out
nAddress[n-20];
int counter = 0;
int lastnum;
for (int i = 0; i < index-2; i++)
{
    //string myval;
    //ostringstream convert;
    //counter++;
    //convert << counter ;

    nAddress[n] = i + 65;   //this is the line that gives the letters... it comes in with an A as the first file FYI
    //nAddress = nAddress + convert.str();
    //cout<<convert.str();
    //cout<<counter;
    //myval = nAddress[n];
    //cout<<myval;

    cout<<"Outputting sub-files...n" <<endl;
    cout<<nAddress<< "n" << endl;
    size_t origsize = strlen(nAddress.c_str()) + 1;
    size_t convertedChars = 0;
    wchar_t wcstrings[newsize];
    mbstowcs_s(&convertedChars, wcstrings, origsize, nAddress.c_str(), _TRUNCATE);
    wcscat_s(wcstrings, L"");

    ofstream outFile (wcstrings);   
    outFile << files[i];
}

这样的:

std::string getPartFilename(int partNumber)
{
    std::ostringstream oss;
    oss << "Test" << partNumber;
    return oss.str();
}

为了澄清我的观点:重构你的代码,删除所有那些讨厌的c字符串操作(strcpy_s(), strcat_s()等)来构建文件名,并使用一个简单直接的c++标准机制来格式化字符串,因为你需要它们。

好的,那么

nAddress[n] = i + 65; 

是真正设置文件递增字母的地方,那么我将这样做:

因为你使用std:string,

// make your address just "test"
nAddress[n] = '';
// cast `i` to a string and concatinate
nAddress += to_string(i);

http://www.cplusplus.com/reference/string/to_string/
http://www.cplusplus.com/reference/string/string/operator + =/


如果你没有使用std:string,你可以这样处理它

// make your address just "test"
nAddress[n] = '';  
// make a character array that contains the character representation of `i`
char buffer[50];
sprintf("%d", i);
// concatinate
strcat(nAddress, buffer);

或者,你可以只做

sprintf(&nAddress[n], "%d", i); 

as individual mention


要将字母更改为数字(如果我理解正确的话),

nAddress[n] = i + 65;

变成

nAddress[n] = i + '0';