将.txt文件列读入数组

这是一种使用操作符>>封装和重载的方法。我假设你所描述的输入只是一长串空格分隔的输入值，第一个值是玩家的数量。

#include <iostream>
#include <iomanip>
#include <string>
#include <sstream>
#include <fstream>
#include <ctype.h>
using namespace std;
static const size_t MaxNumPlayers = 50;
// C++ is about encapsulation, and the player data is
// discrete yet related, so encapsulate it.
struct Player
{
    string m_name;
    int m_scores[5];
    size_t GetNumScores() const { return sizeof(m_scores) / sizeof(m_scores[0]); }
    int m_time;
};
// This allows us to write an operator that will read a player
// directly from an ifstream.
std::ifstream& operator>>(ifstream& istr, Player& player)
{
    istr >> player.m_name;
    for(size_t i = 0; i < player.GetNumScores(); ++i)
    {
       istr >> player.m_scores[i];
    }
    istr >> player.m_time;
    cout << "player: " << player.m_name << ", " << player.m_scores[0] << " @ " << player.m_time << endl;
    return istr;
}
int main(int argc, const char** argv)
{
    ifstream myfile("G2347M.txt");
    if (!myfile)
    {
         cout<<"Could not open file. n";
         system("Pause");
         return -1;
    }
    // We can read the number of players directly.
    size_t numPlayers = 0;
    myfile >> numPlayers;
    if (numPlayers <= 0 || numPlayers > MaxNumPlayers) {
        cout << "Invalid number of players in score file ("<<numPlayers<<")." << endl;
        system("Pause");
        return -1;
    }
    Player players[MaxNumPlayers];
    size_t playersRead = 0;
    while (!myfile.eof())
    {
        myfile >> players[playersRead++];
        if (playersRead >= numPlayers)
            break;
        // drain any spaces after the player.
        while(isspace(myfile.peek()))
          myfile.ignore();
    }
    if (playersRead != numPlayers)
    {
        cout << "Problem reading score file, expected " << numPlayers << " but read " << playersRead << endl;
        system("Pause");
        return -1;
    }
    cout<<"Welcome to the Score Sorting Program! I read "<<playersRead<<" players."<<endl;
    cout<<"Please choose a number that corresponds with the way you would like to sort."<<endl;
    cout<<"You may also search by player if you know their username.n"<<endl;
    /* ... */
    system("Pause");
    return 0;
}

为什么50个球员只有27个分数?

我假设第一行是你希望阅读的行数?如果是这样，您可以动态地分配数组来保存所有数据，而不是仅仅处理50(或27)行。您还可以将一行的所有数据合并到一个结构体中，而不是将其分散到一堆不相连的数组中。

伪代码:

int lineNo = 1;
int totalLines = -1; /* not set */
while(line = read_a_line()) {
    if (lineNo == 1) {
        totalLines = convert_line_text_to_number();
    }
    else {
        /* split the line into "tokens" separated by white space */
        /* store each token in the correct array */
    }
    lineNo++;
    /* if lineNo is too big, break the loop */
}

使用它的最好方法是使用向量。但正如你所说，你必须使用数组，所以这里是它的代码。

#include <iostream>
#include <fstream>
#include <sstream>
using namespace std;
int main()
{
    ifstream file;
    file.open("sample.txt");
    string name[50];
    int score1[27],score2[27],score3[27],score4[27],score5[27],time[27];

    int i = 0;
    while(!file.eof())
    {
        string line;
        getline(file,line);
        char* a = const_cast<char*>(line.c_str());  
        char* pch = strtok (a," ");
        name[i] = pch;
        int counter = 1;
        while (counter < 7)
        {
            pch = strtok (NULL, " ");
            if(counter == 1)
            {
                score1[i] = atoi(pch);
            }
            else if(counter == 2)
            {
                score2[i] = atoi(pch);
            }
            else if(counter == 3)
            {
                score3[i] = atoi(pch);
            }
            else if(counter == 4)
            {
                score4[i] = atoi(pch);
            }
            else if(counter == 5)
            {
                score5[i] = atoi(pch);
            }
            else if(counter == 6)
            {
                time[i] = atoi(pch);
            }
            ++counter;
        }
        ++i;
    }
    //cout<<a;
    return 0;
}

如果你有任何问题请告诉我。我还没有添加一些基本的完整性检查，比如文件检查，请在你的版本中做。