Thread_local std::unique_ptr释放未调用析构函数

thread_local std::unique_ptr release not calling destructor

本文关键字：析构函数 释放 调用 unique local std Thread ptr      更新时间：2023-10-16

为什么在这段代码中没有调用析构函数:

#include <iostream>
#include <thread>
#include <memory>
class base {
    public:
        base() {
            std::cout << "base()" << std::endl;
        }
        virtual ~base() {
            std::cout << "~base()" << std::endl;
        }
        base(const base&) = delete;
        base(base&&) = delete;
        base& operator=(const base&) = delete;
        base& operator=(base&&) = delete;
};
class derived final : public base {
    public:
        derived() {
            std::cout << "derived()" << std::endl;
        }
        virtual ~derived() {
            std::cout << "~derived()" << std::endl;
        }
};

void foo() {
    static thread_local std::unique_ptr<base> ptr;
    if (!ptr) {
        std::cout << "new ptr:" << std::this_thread::get_id() << std::endl;
        ptr.reset(new derived());
    } else {
        std::cout << "release ptr:" << std::this_thread::get_id() << std::endl;
        ptr.release();  // I would expect the destructor to be called here?!
    }
}
void thread_main() {
    foo();
    foo();
}
int main()
{
    std::thread thread1(thread_main);
    thread1.join();
    return 0;
}
输出:

new ptr:140671459997440
base()
derived()
release ptr:140671459997440

我希望:

new ptr:140671459997440
base()
derived()
release ptr:140671459997440
~derived()
~base()

使用gcc 4.9.1

将ptr.release();替换为ptr.reset();

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